Matemáticas 1 · Tema 4
Monomios
Video
Ejemplo
Resuelve las siguientes operaciones con monomios:
$(4x^6y^2)(-3x^5y^3a) = $ $-12x^{11}y^5a$
$(-4x^2y^3a)^2 = $ $16x^4y^6a^2$
$\dfrac{-15x^3y^3a^5}{30x^8y^3a} = $ $\dfrac{-5a^4}{10x^5}$
$\sqrt{36x^8y^4b^2} = $ $6x^4y^2b$
$6x-2x^2+3-2y^2-5x+1-x^2 = $ $-3x^2+x-2y^2+4$
$(-4x^2y^3a)^2 = $ $16x^4y^6a^2$
$\dfrac{-15x^3y^3a^5}{30x^8y^3a} = $ $\dfrac{-5a^4}{10x^5}$
$\sqrt{36x^8y^4b^2} = $ $6x^4y^2b$
$6x-2x^2+3-2y^2-5x+1-x^2 = $ $-3x^2+x-2y^2+4$
Ejercicios
Bloque 1
$(-7x^4y^2)(-5x^6a^3)=$
$(3x^2y^4a^3)^2=$
$\dfrac{-2x^7y^9a}{15x^2ya}=$
$\sqrt{36x^{10}y^4a^2}=$
$-8x+6x-9x^2-2y^2-8+10-y=$
$(3x^2y^4a^3)^2=$
$\dfrac{-2x^7y^9a}{15x^2ya}=$
$\sqrt{36x^{10}y^4a^2}=$
$-8x+6x-9x^2-2y^2-8+10-y=$
Bloque 2
$(5x^6y^5)(-2x^4a^2)=$
$(-5x^2y^6a)^2=$
$\dfrac{-12x^3y^2a^7}{20x^9y^2a^3}=$
$\sqrt{25x^8y^{12}b^6}=$
$-3x+2x^2-8+y^2+8x+6-x^2=$
$(-5x^2y^6a)^2=$
$\dfrac{-12x^3y^2a^7}{20x^9y^2a^3}=$
$\sqrt{25x^8y^{12}b^6}=$
$-3x+2x^2-8+y^2+8x+6-x^2=$
Bloque 3
$(-6x^4y^3)(-2x^5y^2b)=$
$(-6x^4y^3b)^3=$
$\dfrac{-4x^5ya}{12y^6x^2a}=$
$\sqrt[3]{-8x^{12}y^9b^3}=$
$5x-4+2x^2-3x-7x^2+5-y=$
$(-6x^4y^3b)^3=$
$\dfrac{-4x^5ya}{12y^6x^2a}=$
$\sqrt[3]{-8x^{12}y^9b^3}=$
$5x-4+2x^2-3x-7x^2+5-y=$
Bloque 4
$(4x^7y^2)(-3x^6y^2a)=$
$(-4x^3y^4a^2)^3=$
$\dfrac{20x^4y^6a^3}{-50x^7a^6y^6}=$
$\sqrt[3]{-125x^{24}y^6b^3}=$
$2x-3+6x^2-7x+2x^2+8=$
$(-4x^3y^4a^2)^3=$
$\dfrac{20x^4y^6a^3}{-50x^7a^6y^6}=$
$\sqrt[3]{-125x^{24}y^6b^3}=$
$2x-3+6x^2-7x+2x^2+8=$
Respuestas
▼Bloque 1
$(-7x^4y^2)(-5x^6a^3) = $ $35x^{10}y^2a^3$
$(3x^2y^4a^3)^2 = $ $9x^4y^8a^6$
$\dfrac{-2x^7y^9a}{15x^2ya} = $ $\dfrac{-2x^5y^8}{15}$
$\sqrt{36x^{10}y^4a^2} = $ $6x^5y^2a$
$-8x+6x-9x^2-2y^2-8+10-y = $ $-9x^2-2x-2y^2-y+2$
$(3x^2y^4a^3)^2 = $ $9x^4y^8a^6$
$\dfrac{-2x^7y^9a}{15x^2ya} = $ $\dfrac{-2x^5y^8}{15}$
$\sqrt{36x^{10}y^4a^2} = $ $6x^5y^2a$
$-8x+6x-9x^2-2y^2-8+10-y = $ $-9x^2-2x-2y^2-y+2$
Bloque 2
$(5x^6y^5)(-2x^4a^2) = $ $-10x^{10}y^5a^2$
$(-5x^2y^6a)^2 = $ $25x^4y^{12}a^2$
$\dfrac{-12x^3y^2a^7}{20x^9y^2a^3} = $ $\dfrac{-3a^4}{5x^6}$
$\sqrt{25x^8y^{12}b^6} = $ $5x^4y^6b^3$
$-3x+2x^2-8+y^2+8x+6-x^2 = $ $x^2+5x+y^2-2$
$(-5x^2y^6a)^2 = $ $25x^4y^{12}a^2$
$\dfrac{-12x^3y^2a^7}{20x^9y^2a^3} = $ $\dfrac{-3a^4}{5x^6}$
$\sqrt{25x^8y^{12}b^6} = $ $5x^4y^6b^3$
$-3x+2x^2-8+y^2+8x+6-x^2 = $ $x^2+5x+y^2-2$
Bloque 3
$(-6x^4y^3)(-2x^5y^2b) = $ $12x^9y^5b$
$(-6x^4y^3b)^3 = $ $-216x^{12}y^9b^3$
$\dfrac{-4x^5ya}{12y^6x^2a} = $ $\dfrac{-x^3}{3y^5}$
$\sqrt[3]{-8x^{12}y^9b^3} = $ $-2x^4y^3b$
$5x-4+2x^2-3x-7x^2+5-y = $ $-5x^2+2x-y+1$
$(-6x^4y^3b)^3 = $ $-216x^{12}y^9b^3$
$\dfrac{-4x^5ya}{12y^6x^2a} = $ $\dfrac{-x^3}{3y^5}$
$\sqrt[3]{-8x^{12}y^9b^3} = $ $-2x^4y^3b$
$5x-4+2x^2-3x-7x^2+5-y = $ $-5x^2+2x-y+1$
Bloque 4
$(4x^7y^2)(-3x^6y^2a) = $ $-12x^{13}y^4a$
$(-4x^3y^4a^2)^3 = $ $-64x^9y^{12}a^6$
$\dfrac{20x^4y^6a^3}{-50x^7a^6y^6} = $ $\dfrac{-2}{5x^3a^3}$
$\sqrt[3]{-125x^{24}y^6b^3} = $ $-5x^8y^2b$
$2x-3+6x^2-7x+2x^2+8 = $ $8x^2-5x+5$
$(-4x^3y^4a^2)^3 = $ $-64x^9y^{12}a^6$
$\dfrac{20x^4y^6a^3}{-50x^7a^6y^6} = $ $\dfrac{-2}{5x^3a^3}$
$\sqrt[3]{-125x^{24}y^6b^3} = $ $-5x^8y^2b$
$2x-3+6x^2-7x+2x^2+8 = $ $8x^2-5x+5$
Ejercicios extra
▼Bloque 5
$(-10x^5y^3)(6x^4y^2b)=$
$(3x^4y^2a)^3=$
$\dfrac{-8x^7y^6a^4}{24x^3y^2a^2}=$
$\sqrt{81x^{10}y^8a^6}=$
$-6x+7x-4x^2+3y^2-8+9-2y=$
$(3x^4y^2a)^3=$
$\dfrac{-8x^7y^6a^4}{24x^3y^2a^2}=$
$\sqrt{81x^{10}y^8a^6}=$
$-6x+7x-4x^2+3y^2-8+9-2y=$
Bloque 6
$(7x^4y^6)(-9x^3b^2)=$
$(-2x^3y^5b)^3=$
$\dfrac{-5x^6y^7b^8}{15x^2y^4b^3}=$
$\sqrt{49x^6y^{12}b^4}=$
$8x-3x^2+5y^2-7x+10-2x^2-y=$
$(-2x^3y^5b)^3=$
$\dfrac{-5x^6y^7b^8}{15x^2y^4b^3}=$
$\sqrt{49x^6y^{12}b^4}=$
$8x-3x^2+5y^2-7x+10-2x^2-y=$
Bloque 7
$(-7x^3y^4)(4x^6y^3a)=$
$(-5x^2y^4b)^2=$
$\dfrac{-12x^8ya^3}{36x^4a^2y^2}=$
$\sqrt[3]{-27x^9y^6b^3}=$
$9x+3x^2-5x-6x^2+7+2y-3=$
$(-5x^2y^4b)^2=$
$\dfrac{-12x^8ya^3}{36x^4a^2y^2}=$
$\sqrt[3]{-27x^9y^6b^3}=$
$9x+3x^2-5x-6x^2+7+2y-3=$
Bloque 8
$(5x^5y^2)(-8x^4y^3a)=$
$(-4x^3y^2a^4)^2=$
$\dfrac{18x^6y^7a^3}{54x^9a^6y^5}=$
$\sqrt[3]{-64x^{12}y^9b^6}=$
$3x-2+5x^2-6x+4x^2+7=$
$(-4x^3y^2a^4)^2=$
$\dfrac{18x^6y^7a^3}{54x^9a^6y^5}=$
$\sqrt[3]{-64x^{12}y^9b^6}=$
$3x-2+5x^2-6x+4x^2+7=$