Matemáticas 1 · Tema 2
Jerarquía de operaciones
Video
Ejemplo
Resuelve aplicando la jerarquía de operaciones:
$$\begin{aligned}
-5+6(-3+8)-4(-3)(2)-5(-3)^2 &= \\
-5+6(5)+24-5(9) &= \\
-5+30+24-45 &= \\
-50+54 &= \mathbf{4}
\end{aligned}$$
$$\begin{aligned}
2[-5(-3(-2+8))] &= \\
2[-5(-3(6))] &= \\
2[-5(-18)] &= \\
2[90] &= \mathbf{180}
\end{aligned}$$
Ejercicios
Bloque 1
$4-2(-1)(-5)+6(-1+4)-3(-5)^2=$
$5(-2)(3)+4(-1-5)-3+4(-1)^2=$
$5[-3(4(-1-2))]=$
$-3[2(-5(-4+10))]=$
$5(-2)(3)+4(-1-5)-3+4(-1)^2=$
$5[-3(4(-1-2))]=$
$-3[2(-5(-4+10))]=$
Bloque 2
$8-6(3-4)-2(3)^2+2(6)(-1)=$
$3(-2)^4+6-3(-4)(-1)+7(-3+10)=$
$4[-3(2(-10+4))]=$
$-6[5(-4(3+7))]=$
$3(-2)^4+6-3(-4)(-1)+7(-3+10)=$
$4[-3(2(-10+4))]=$
$-6[5(-4(3+7))]=$
Respuestas
▼Bloque 1
$$\begin{aligned}
4-2(-1)(-5)+6(-1+4)-3(-5)^2 &= \\
4-10+6(3)-3(25) &= \\
4-10+18-75 &= \\
22-85 &= \mathbf{-63}
\end{aligned}$$
$$\begin{aligned}
5(-2)(3)+4(-1-5)-3+4(-1)^2 &= \\
-30+4(-6)-3+4(1) &= \\
-30-24-3+4 &= \\
-57+4 &= \mathbf{-53}
\end{aligned}$$
$$\begin{aligned}
5[-3(4(-1-2))] &= \\
5[-3(4(-3))] &= \\
5[-3(-12)] &= \\
5[36] &= \mathbf{180}
\end{aligned}$$
$$\begin{aligned}
-3[2(-5(-4+10))] &= \\
-3[2(-5(6))] &= \\
-3[2(-30)] &= \\
-3[-60] &= \mathbf{180}
\end{aligned}$$
Bloque 2
$$\begin{aligned}
8-6(3-4)-2(3)^2+2(6)(-1) &= \\
8-6(-1)-2(9)-12 &= \\
8+6-18-12 &= \\
14-30 &= \mathbf{-16}
\end{aligned}$$
$$\begin{aligned}
3(-2)^4+6-3(-4)(-1)+7(-3+10) &= \\
3(16)+6-12+7(7) &= \\
48+6-12+49 &= \\
103-12 &= \mathbf{91}
\end{aligned}$$
$$\begin{aligned}
4[-3(2(-10+4))] &= \\
4[-3(2(-6))] &= \\
4[-3(-12)] &= \\
4[36] &= \mathbf{144}
\end{aligned}$$
$$\begin{aligned}
-6[5(-4(3+7))] &= \\
-6[5(-4(10))] &= \\
-6[5(-40)] &= \\
-6[-200] &= \mathbf{1200}
\end{aligned}$$
Ejercicios extra
▼Bloque 3
$-4(-3)(-2)-3(-2+6)+5-4(-3)^2=$
$6(2)(-5)+7(8-4)-3+5(2)^3=$
$4-3(5)(-2)+6(-9+7)-7(-4)^2=$
$-5(4)(3)+6(2-9)-2+8(5)^3=$
$7+5(3)(-6)-4(8-5)+9(2)^2=$
$-4[-5(-3(-2+8))]=$
$7[-3(4(5+1))]=$
$-6[5(-2(3-7))]=$
$8[-6(2(4+3))]=$
$-5[3(-7(6-2))]=$
$6(2)(-5)+7(8-4)-3+5(2)^3=$
$4-3(5)(-2)+6(-9+7)-7(-4)^2=$
$-5(4)(3)+6(2-9)-2+8(5)^3=$
$7+5(3)(-6)-4(8-5)+9(2)^2=$
$-4[-5(-3(-2+8))]=$
$7[-3(4(5+1))]=$
$-6[5(-2(3-7))]=$
$8[-6(2(4+3))]=$
$-5[3(-7(6-2))]=$
Bloque 4
$-6(5)(-4)+7(2-6)-8+3(4)^2=$
$9(3)(-2)-5(7)^3+6(5-1)+2=$
$-4+6(-8)^2-3(2-7)+5(3)(-6)=$
$8-7(4)(-3)+9(6-2)-5(2)^3=$
$-3(2)(5)+6+4(-9+3)-7(3)^2=$
$-7[-4(6(-2+9))]=$
$6[-5(3(7+4))]=$
$-8[3(-6(5-2))]=$
$5[-3(2(4+6))]=$
$-4[6(-5(1+3))]=$
$9(3)(-2)-5(7)^3+6(5-1)+2=$
$-4+6(-8)^2-3(2-7)+5(3)(-6)=$
$8-7(4)(-3)+9(6-2)-5(2)^3=$
$-3(2)(5)+6+4(-9+3)-7(3)^2=$
$-7[-4(6(-2+9))]=$
$6[-5(3(7+4))]=$
$-8[3(-6(5-2))]=$
$5[-3(2(4+6))]=$
$-4[6(-5(1+3))]=$